Question

Alguém pode responder por favor e calcula também?

Answer 1

Explicação passo a passo:

a)

$log (3)^5 \\=5.log(3)\\=5.0,4771\\=2,3855$

b)

$log \frac{5}{2} \\=log (5)-log(2)\\=log(\frac{10}{2} )-0,3010\\=log(10)-log(2)-0,3010\\=1-0,3010-0,3010\\=0,398$

c)

$log(\sqrt{3})\\=log(3)^\frac{1}{2} \\\\=\frac{1}{2}.log (3)\\=\frac{1}{2}.0,4771\\\\=0,23855$

d)

$log(108)\\=log(2^2.3^3)\\=log(2)^2+log(3)^3\\=2.log(2)+3.log(3)\\=2.0,3010+3.0,4771\\=0,602 +1,4313\\=2,0333$