Question

ALGUÉM PODE RESOLVER PRA MIM, POR FAVOR.

1b5c08e8c9b40190c6b0b6ffb0e0dbb0.pdf

Answer 1

Resposta:

1)

a)

x²-19x=0

x*(x-19)=0

x'=0

x-19=0 ==>x''=19

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b)

3x²-12x=0

3x*(x-4)=0

3x=0 ==>x'=0

x-4=0 ==>x''=4

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c)

7x²+14x=0

7x*(x+2)=0

7x=0 ==>x'=0

x+2=0 ==>x''=-2

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d)

5x²+9x=0

x*(5x+9)=0

x'=0

5x+9=0 ==>x''=-9/5

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e)

x²+4x=0

x*(x+4)=0

x'=0

x+4=0 ==>x''=-4

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f)

6x²+18x=0

6x*(x+3)=0

6x=0 ==>x'=0

x+3=0 ==>x''=-3

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g)

x²-x=0

x*(x-1)=0

x'=0

x-1=0 ==>x''=1

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h)

4x²+10x=0

x*(4x+10)=0

x'=0

4x+10=0  ==>x''=-10/4=-5/2