Question

Alguem pode mim ajuda a responder?​

Answer 1

b) $\frac{7^9} {7^{6} } =7^{3} =343$

c) $\sqrt[3]{3^{6} } =3^{\frac{6}{3} } =3^{2} =9$

d) $(\frac{2}{4} )^{-9} =(\frac{4}{2} )^{9} =\frac{4^{9} }{2^{9} } =\frac{262144}{512} =512$

e) $\frac{3^{5} .3^{8} }{3^{7} } =\frac{3^{5+8} }{3^{7} } =\frac{3^{13} }{3^{7} } =3^{13-7} =3^{6} =729$

f) $\frac{5^{-3};5^{4} }{5^{0} } =\frac{(\frac{1}{5})^{3}.5^{4} }{5^{0} } =\frac{(\frac{1}{125} ).625}{1} =\frac{(\frac{625}{125} )}{1} =\frac{5}{1} =5$

g) $\sqrt{\frac{5^{4} }{25} } ={\frac{5^{\frac{4}{2} } }{25^{\frac{4}{2} } } } =\frac{5^{2} (:5) }{25^{2} (:5)} =\frac{1^{2} }{5^{2} } =\frac{1}{25}$

h) $\frac{(3^{2})^{5}}{9^{2} } =\frac{3^{2.5} }{9^{2} } =\frac{3^{10}}{9^{2}}=\frac{59049}{81} =729$

i) $(\frac{3}{2} )^{-3} =(\frac{2}{3}) ^{3} =\frac{2^{3} }{3^{3} } =\frac{8}{27}$