Matemática, perguntado por dudu47347, 10 meses atrás

alguem pode me reponder esses mmc A (4,6,9,15) (2,10,15,45) (8,36,28,72) (54,96,10,18) (20,3048,120)

Soluções para a tarefa

Respondido por CyberKirito
1

a)

4,6,9,15|2

2,3,9,15|2

1,3,9,15|3

1,1,3,5|3

1,1,1,5|5

1,1,1,1

mmc(4,6,9,15)=2×2×3×3×5=180

b)

2,10,15,45|2

1,5,15,45|3

1,5,5,15|3

1,5,5,5|5

1,1,1,1

mmc(2,10,15,45)=2×3×3×5=90

c)

8,36,28,72|2

4,18,14,36|2

2,9,7,18|2

1,9,7,9|3

1,3,7,3|3

1,1,7,1|7

1,1,1,1

mmc(8,36,28,72)=2×2×2×3×3×7=504

d)

54,96,10,18|2

27,48,5,9|2

27,24,5,9|2

27,12,5,9|2

27,6,5,9|2

27,3,5,9|3

9,1,5,3|3

3,1,5,1|3

1,1,5,1|5

1,1,1,1

mmc(54,96,10,18)=2×2×2×2×2×3×3×3×5=4320

e)

20,3048,120|2

10,1524,60|2

5,762,30|2

5,381,15,|3

5,127,5,|5

1,127,1|127

1,1,1

mmc(20,3048,60)=2×2×2×3×5×127=15240

Perguntas interessantes