Question

alguém pode me ajudar pfvr ? ⚠️ Urgente ⚠️


Eu Imploro Pfvr​

Answer 1

Resposta:

x + 1=0

x + 1-1 =0

x = 0-1

x= -1

x² + 2x = -1

x²  + 2x -(-1) = 0

x²  + 2x + 1=0

(x + 1)²  = 0

x + 1= 0

x = -1

10) $(x) \frac{4}{3}m$

9) c)

$(x + 1(x-3)= 0\\x(x-1)+1(x-3)=0\\x^{2} -3x +1(x-3)=0\\x^{2} -3x + x-3 =0\\x^{2} -2x -3=0\\x=\frac{-b±\sqrt{b^{2} -4ac} }{2a}\\\\x^{2} -2x -3= 0\\a=1\\b=-2\\c=-3\\\\x=\frac{-(-2)±\sqrt{(-2)^{2}-4.1.1(-3) } }{2.1} \\\\x= \frac{2±\sqrt{4-4.1(-3)} }{2.1} \\\\x = \frac{2±\sqrt{4+12} }{2.1}\\\\x= \frac{2±\sqrt{16} }{2.1}\\\\x= \frac{2±4}{2.1}\\\\x = \frac{2±4}{2}\\\\x= \frac{2+4}{2}\\\\x= \frac{2-4}{2}\\\\x= 3\\x=-1$

Explicação passo-a-passo: