Question

alguem pode me ajudar? (olha a foto das questões)

Answer 1

y/4 + 1 = 7 - y/2
y/4 + y/2 + 1 - 7 = 0
(1/4 + 1/2)y - 6 = 0
3/4y = 6
y = 6 * 4/3
y = 8

(x - 2)/4 + (x - 3)/2 = (x - 1)/3 + x/6
(x - 2)/4 + (x - 3)/2 - (x - 1)/3 - x/6 = 0
3(x - 2)/(3*4) + 6(x - 3)/(2*6) - 4(x - 1)/(3*4) - 2x/(6*2) = 0
(3x - 6 + 6x - 18 - 4x + 4 - 2x)/12 = 0
(3x - 20)/12 = 0
3x - 20 = 0
3x = 20
x = 20/3

2(x + 1)/3 - 3(x + 1)/2 = (x + 2)/6
(2x + 2)/3 - (3x + 3)/2 - (x + 2)/6 = 0
2(2x + 2)/(3*2) - 3(3x + 3)/(2*3) - (x + 2)/6 = 0
(4x + 4 - 9x - 9 - x - 2)/6 = 0
(- 6x - 7)/6 = 0
- 6x - 7 = 0
6x = - 7
x = - 7/6