Question

alguém pode me ajudar nessa questão :)​

Answer 1

4)

A)

$(10xy) \div (5x) = \\ \\ 2 {x}^{1 - 1} y = \\ \\ 2( {x)}^{0} y = \\ \\ 2(1)y = \\ \\ \blue{ 2y}$

B)

$( {x}^{3} {y^{2} } ) \div (2xy) = \\ \\ \dfrac{1}{2} {x}^{3 - 1} {y}^{2 - 1} = \\ \\ \dfrac{1}{2} {x}^{2} {y}^{1 } = \\ \\ \blue{ \dfrac{ {x}^{2}y }{2} }$

C)

$( - 3x {z}^{2} ) \div ( - 3xz) = \\ \\ {x}^{1 - 1} {z}^{2 - 1} = \\ \\ {x}^{0} {z}^{1} = \\ \\ 1(z) = \\ \\ \blue{z}$

D)

$( - 14 {m}^{6} {n}^{3} ) \div (7 {m}^{4} {n}^{2} ) = \\ \\ - 2 {m}^{6 - 4} {n}^{3 - 2} \\ \\ - 2 {m}^{2} {n}^{1} = \\ \\ \blue{ - 2 {m}^{2} n}$

E)

$( \dfrac{1}{2} {a}^{3} {b}^{2} ) \div ( - {a}^{3} {b}^{2} ) = \\ \\ - \dfrac{1}{2} {a}^{3 - 3} {b}^{2 - 2} = \\ \\ - \dfrac{1}{2} {a}^{0} {b}^{0 } = \\ \\ - \dfrac{ 1}{2} (1)(1) = \\ \\ \blue{ - \dfrac{1}{2} }$

F)

$( {a}^{4} {b}^{3} ) \div (5 {a}^{3} b) = \\ \\ \dfrac{1}{5} {a}^{4 - 3} {b}^{3 - 1} = \\ \\ \dfrac{1}{5} {a}^{1} {b}^{2} = \\ \\ \blue{\dfrac{a {b}^{2} }{5} }$

G)

$( - 3 {x}^{5} {y}^{3} ) \div ( - 4 {x}^{2} y) = \\ \\ \dfrac{3}{4} {x}^{5 - 2} {y}^{3 - 1} = \\ \\ \blue{ \dfrac{3}{4} {x}^{3} {y}^{2} }$

Bons Estudos!