Question

Alguém pode me ajudar na simplificação de radicais

Answer 1

a) ∛x¹¹ = ∛x³.x³.x³.x² = x³∛x²

b) √2³ = √2.2² = 2√2

c) ∛2⁴.3⁵ = 2.3∛2.3² = 6∛2.3²

d) √48a⁵ = √2⁴.3.a⁵ = 2².a²√3a = 4a²√3a

e) $\sqrt[4]{243a^5}$ = $\sqrt[4]{3^5.a^5}$ = $3a\sqrt[4]{3a}$

Answer 2

Resposta:

$a)\\ \sqrt[3]{x^{11}} =\sqrt[3]{x^3.x^3.x^3.x^2} =x.x.x\sqrt[3]{x^2} =x^3\sqrt[3]{x^2} \\ \\ b)\\ \sqrt{2^3} =\sqrt{2^2.2} =2\sqrt{2} \\ \\ c)\\ \sqrt[3]{2^4.3^5} =\sqrt[3]{2^3.2.3^3.3^2} =2.3\sqrt[3]{2.3^2} =6\sqrt[3]{2.3^2} \\ \\ d)\\ \sqrt{48a^5} =\sqrt{2^2.2^2.3.a^2.a^2.a} =2.2.a.a\sqrt{3a} =4a^2\sqrt{3a} \\ \\ e)\\ \sqrt[4]{243a^5} =\sqrt[4]{3^4.3.a^4.a} =3a\sqrt[4]{3a}$