Question

alguém pode me ajudar com essa equação por favor
x² -7x + 12=0

Answer 1

$x^2 - 7x + 12 = 0 \\ \\ a = 1 \\ b = -7 \\ c = 12 \\ \\ x = \frac{-b\pm \sqrt{b^2-4.a.c} }{2.a} \\ \\ x = \frac{-(-7)\pm \sqrt{(-7)^2-4.1.12} }{2.1} \\ \\ x = \frac{7\pm \sqrt{49-48} }{2} \\ \\ x = \frac{7\pm1}{2} \\ \\ \\ x' = \frac{7+1}{2} \rightarrow x' = \frac{8}{2} \rightarrow x' = 4 \\ \\ x'' = \frac{8-1}{2} \rightarrow x''= \frac{6}{2} \rightarrow x'' = 3$

Raízes:

$x' = 4 \\ x'' = 3$

Answer 2

∆ = (-7)^2 - 4 × 1 × 12
∆ = 49 - 48 = 1

X' = (-(-7) + √∆) / 2 × 1
X' = (7 + √1) / 2
X' = (7 + 1) / 2
X' = 8 / 2 = 4

X" = (-(-7) - √∆) / 2 × 1
X" = (7 - 1) / 2
X" = 6 / 2 = 3