Question

Alguem pode me ajudar a resolver??

Answer 1

$9^ \frac{3}{2}=(3^2) ^ \frac{3}{2} = 3^\frac{2*3}{2} = 3^3\\\\8^ \frac{4}{3} = (2^3)^ \frac{4}{3} = 2^{ \frac{3*4}{3} }= 2^4\\\\ 81^ {0,25} = (9^2)^{- \frac{1}{4} }=9^{ -\frac{1}{2} }= (3^2)^{ -\frac{1}{2} }= 3^{-1}\\\\ (16^{ \frac{5}{4} })^ \frac{2}{5}= 16^{ \frac{5}{4}* \frac{2}{5} } = 16^ \frac{1}{2}= (4^2)^ \frac{1}{2} = 4^1 = 4=2^2$