Question

Alguém pode me ajudar???

Answer 1

Resposta:

$a)\\ 4^2-10+(2^3-5)=\\ \\ 16-10+(8-5)=\\ \\ 16-10+3=\\ \\ 19-10=\boxed{9}$

$b)\\ 30-(2+1)^2+2^3+4^2=\\ \\ 30-(3)^2+8+16=\\ \\ 30-9+8+16=\\ \\ 30+8+16-9=\\ \\ 54-9=\boxed{45}$

$c)\\ 30+[6^2\div(5-3)+1]=\\ \\ 30+[36\div2+1]=\\ \\ 30+[18+1]=\\ \\ 30+19=\boxed{49}$