Question

alguém pode me ajudar?

Answer 1

$Ola'~~\mathbb{BIA} \\ \\ Da~figura, por~propriedade: \\ \\ (2x+10)+y=180\° \\ \\ 2x+y=180-10 \\ \\ 2x+y=170\°~~---\ \textgreater \ isolando~(y)~temos \\ \\ \boxed{y=170\°-2x}~~----\ \textgreater \ (I) \\ \\ =======================================$

$Da~figura~a~soma~dos~\~angulos~internos~e'~igual~a~180\°, vejamos: \\ \\ 180-(2x+10)+x+310-3x=180\°~~~---\ \textgreater \ desenvolvendo \\ \\ -4x=-300 \\ \\ \boxed{\boxed{x=75\°}} \\ \\ Substituindo~o~valor~(x)~em~(I)~para~calcular~o~valor~(y)~temos: \\ \\ y=170-2x \\ \\ y=170-2(75\°)$

$y=170-150 \\ \\ \boxed{\boxed{y=20\° }} \\ \\ Agora~nos~disse~a~soma~dos~\~angulos~[x~~e~~y~~]~e' \\ \\ x+y=75\°+20\° \\ \\\boxed{ \boxed{x+y=95\°}}~~---\ \textgreater \ opc\~ao~\textcircled{b} \\ \\ \mathbb{ttttttttttttttttttttttttttttttttttttttt}\\ ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~Espero~ter~ajudado!!$