Question

ALGUEM PODE AJUDAR POR FAVOR?

Answer 1

$10^{ \frac{3x-1}{x^2+1} }-10=0$

$10^{ \frac{3x-1}{x^2+1} =10^1$

$\frac{3x-1}{x^2+1} =1$

$x^{2} +1=3x-1$

$x^{2} -3x+2=0$

$x= \frac{-b\pm \sqrt{b^-4ac} }{2a} = \frac{3\pm \sqrt{9-8} }{2} = \frac{3\pm \sqrt{1} }{2} =$

$x'= \frac{3+1}{2} = \frac{4}{2} =2$

$x"= \frac{3-1}{2} = \frac{2}{2} =1$

S={1,2}