Question

ALGUEM PELO AMOR DE DEUS

3- Reduza os termos semelhantes nas seguintes expressões algébricas:
a) 6x + (2x - 4) - 2
b) 7y-8-(5y - 3) -
c) 4x (-3x + 9 - 2x)
d) 3x - (-2x + 5) - 8x +9
e) 4x3+ (2x + 1)
f) (x+y) - (x + 2y)
g) (3x-2y) + (7x + y)
h)-(8a + 4) (3a + 2)
i) 5a + (3a - 2) - (10a-8)
j) 6x + (5x-7) - (20 + 3x)
k) (x+y+z) + x - (3y+z)
1) (m+2n) - (r-2n)-(n+r)
m) -(6y + 4x) + (3y - 4x)-(-2x + 3y)
n) 6x² - [4x² + (3x - 5) + x]
o) 3x + [2y- [5x - (y + x)]
p) -3x + [x² - (4x²-x)+ 5x]
q) xy - [2x + (3xy - 4x) + 7x]
r) 8a - [(a+2m) - (3a - 3m)]
s) a-(b-c) + [2a + (3b + c)]
t) -[x+(7-x) - (5+2x)]
u) {9x - [4x - (x - y) - 5y]+y}
v) (3a+2m)-[(a-2m) - (6a +2m)]
w) 7x3-(3x²-x-[2x - (5x3 - 6x²) - 4x]}
x) 2y - {3y + [4y - (y-2x) + 3x] - 4x} + 2x​

Answer 1

Resposta:

peguei essas no livro de matemática (r=resposta)

Explicação passo-a-passo:

a) 6x + (2x – 4) – 2= (R: 8x -6)

b) 7y -8 – (5y – 3) = (R: 2y -5)

c) 4x – ( -3X + 9 – 2X) = ( R: 9x – 9)

d) 3x – (-2x + 5) – 8x + 9 = (R: -3x + 4)

e) 4x – 3 + (2x + 1) = (R: 6x -2)

f) (x + y) – (x + 2y) = (R: -y)

g) ( 3x – 2y) + (7x + y) = (R: 10x – 19)

h) –(8a + 4 – ( 3a + 2)= (R: -11a -6)

a) 5a + (3a -2) – (10a – 8) = (R: -2a + 6)

b) 6x + (5x -7) – (20 + 3x )= (R: 8x -27)

c) (x + y + z) + x – (3y + z) = ( R: 2x – 2y)

d) (m + 2n ) – ( r – 2n) – ( n+ r) = (R: m + 3n – 2r)

e) – (6y + 4x ) + ( 3y – 4x ) – (-2x + 3y) = (R: -6y – 6x)

a) 6x² - [ 4x² + (3x – 5) + x]= (R: 2x²- 4x + 5)

b) 3X + { 2Y – [ 5X – (Y + X)]} = (R: -1x + 3y)

c) – 3x + [ x² - ( 4x² - x ) + 5x] = (R: -3x² + 3x )

d) Xy – [ 2x + (3xy – 4x ) + 7x] = (R: 2xy – 5x)

e) 8a – [ ( a + 2m) – ( 3a – 3m)] = (R: 10a – 5m)

f) a– (b – c) + [ 2a + (3b + c)] = (R: 3a + 2b + 2c)

g) –[x + (7 – x) – (5 + 2x)] = (R: -2x -2)

h) { 9x – [ 4x – (x – y)- 5y] + y} = (R: 6x + 5y)

i) (3a + 2m ) – [ ( a – 2m) – (6a + 2m)] = (R: 8a + 6m)

j) 7x³- { 3x² - x – [ 2x – { 5x³ - 6x² ) – 4x ]} = (R: 2x³ + 3x²- 1x)