Alguém me explica como fazer (n+4)!/(n+2)!+(n+3)!
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Temos um caso de fatorial, e para resolver, tentamos reduzir a fim de anular os iguais.... Sabemos que:
![(n+4)!=(n+4)(n+3)(n+2)!\\\\ (n+3)!=(n+3)(n+2)! (n+4)!=(n+4)(n+3)(n+2)!\\\\ (n+3)!=(n+3)(n+2)!](https://tex.z-dn.net/?f=%28n%2B4%29%21%3D%28n%2B4%29%28n%2B3%29%28n%2B2%29%21%5C%5C%5C%5C+%28n%2B3%29%21%3D%28n%2B3%29%28n%2B2%29%21)
![\frac{(n+4)!}{(n+2)!+(n+3)!}\\\\ \frac{(n+4)(n+3)(n+2)!}{(n+2)!+(n+3)(n+2)!}\\\\ \frac{(n+4)(n+3)(n+2)!}{(n+2)!(1+n+3)}\\\\ \frac{(n+4)(n+3)(n+2)!}{(n+4)(n+2)!}\\\\ \boxed{(n+3)} \frac{(n+4)!}{(n+2)!+(n+3)!}\\\\ \frac{(n+4)(n+3)(n+2)!}{(n+2)!+(n+3)(n+2)!}\\\\ \frac{(n+4)(n+3)(n+2)!}{(n+2)!(1+n+3)}\\\\ \frac{(n+4)(n+3)(n+2)!}{(n+4)(n+2)!}\\\\ \boxed{(n+3)}](https://tex.z-dn.net/?f=%5Cfrac%7B%28n%2B4%29%21%7D%7B%28n%2B2%29%21%2B%28n%2B3%29%21%7D%5C%5C%5C%5C+%5Cfrac%7B%28n%2B4%29%28n%2B3%29%28n%2B2%29%21%7D%7B%28n%2B2%29%21%2B%28n%2B3%29%28n%2B2%29%21%7D%5C%5C%5C%5C+%5Cfrac%7B%28n%2B4%29%28n%2B3%29%28n%2B2%29%21%7D%7B%28n%2B2%29%21%281%2Bn%2B3%29%7D%5C%5C%5C%5C+%5Cfrac%7B%28n%2B4%29%28n%2B3%29%28n%2B2%29%21%7D%7B%28n%2B4%29%28n%2B2%29%21%7D%5C%5C%5C%5C+%5Cboxed%7B%28n%2B3%29%7D)
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