Question

Alguém me ajunda Por favor ​

Answer 1

Vamos lá !!

Resoluções :

A )

$6x = 2x + 15$

$6x - 2x = 15$

$4x = 15$

$\red{x = \dfrac{15}{4} }$

B )

$2x - 5 = x + 1$

$2x - x = 1 + 5$

$\red{x = 6}$

C )

$2x + 3 = x + 4$

$2x - x = 4 - 3$

$\red{x = 1}$

D )

$5x + 7 = 4x + 10$

$5x - 4x = 10 - 7$

$\red{x = 3}$

E )

$4x - 10 = 2x + 2$

$4x - 2x = 2 + 10$

$2x = 12$

$x = \dfrac{12}{2}$

$\red{x = 6}$

F )

$4x - 7 = 8x - 2$

$8x - 2 = 4x - 7$

$8x - 4x = - 7 + 2$

$4x = - 5$

$\red{x = \dfrac{ - 5}{4} }$

G )

$2x + 1 = 4x - 7$

$4x - 7 = 2x + 1$

$4x - 2x = 1 + 7$

$2x = 8$

$x = \dfrac{8}{2}$

$\red{x = 4}$

I )

$9x + 9 + 3x = 15$

$9x + 3x = 15 - 9$

$12x = 6$

$\red{x = \dfrac{6}{12} }$

Bons estudos .