Question

Alguém me ajudar a resolver isso pfv???????
A, 3n+50-2n=20+40
B, 2y+5y+6=6y+10
C, x2-5×+16=0
D, x2+2x-35=0
C, x2+3x=0
E, x2-16=0
F, 2x2-32=0

Answer 1

3n+50-2n=20+40

3n-2n=20+40-50

n=10

2y+5y+6=6y+10

2y+5y-6y=10-6

y=4

x2-5×+16=0

dt=b2 -4ac

dt=(-5)2 -4(1)*16

dt=25-64

dt=-39

x não pertence aos números reais

x2+2x-35=0

dt=2(2)-4*1*-35

dt=4+140

dt=144

x=(-b +/-raiz(dt))/2a

x=(-2 +/-raiz(144))/2*1

x=(-2+/-12))/2

x1 =(-2+12)/2

x1 = 10/2 = 5

x2=(-2-12)/2

x2=-14/2 = -7

x2+3x=0

x2 + (b/a)x =0

x+(x + b/a) = 0

x1=0

x2=-b/a

x2 + (3/1)x =0

x+(x + 3/1) = 0

x1=0

x2=-3/1 = -3

x2-16=0

x2=16

×=|raiz(16)|

x=4

2x2-32=0

x2 = -c/a

x2=-(-32)/2

x2=32/2 = 16

x2= 16

x=|raiz(16)|

x=4