Question

alguém me ajudaaa calcule as potências​

Answer 1

${( \frac{1}{3} )}^{ - 3} = { ( \frac{3}{1})}^{3} = {3}^{3} = 27$

${ ( - \frac{5}{4} )}^{ - 3} = ({ - \frac{ 4}{5} )}^{3} = - \frac{ {4}^{3} }{ {5}^{3} } = - \frac{64}{125}$

${( - \frac{1}{3}) }^{ - 2} = ({ - \frac{3}{1} })^{2} = {( - 3)}^{2} = 9$

$( - { \frac{2}{5} })^{ - 3} = ( { - \frac{5}{2} })^{3} = ( - \frac{ {5}^{3} }{ {2}^{3} } ) = - \frac{125}{8}$