Question

Alguém me ajuda por gentileza?

Answer 1

Explicação passo-a-passo:

a) A + B

   $\left[\begin{array}{ccc}1&0\\-2&3\\\end{array}\right]+\left[\begin{array}{ccc}5&3\\2&-4\\\end{array}\right]$

   $\left[\begin{array}{ccc}1+5&0+3\\-2+2&3+(-4)\\\end{array}\right]=\left[\begin{array}{ccc}6&3\\0&-1\\\end{array}\right]$

******************************************************************************

b) 2A

   $2.\left[\begin{array}{ccc}1&0\\-2&3\\\end{array}\right]$

   $\left[\begin{array}{ccc}2.1&2.0\\2.(-2)&2.3\\\end{array}\right]=\left[\begin{array}{ccc}2&0\\-4&6\\\end{array}\right]$

*****************************************************************************

c) B + 3A

   $\left[\begin{array}{ccc}5&3\\2&-4\\\end{array}\right]+3.\left[\begin{array}{ccc}1&0\\-2&3\\\end{array}\right]$

   $\left[\begin{array}{ccc}5&3\\2&-4\\\end{array}\right]+\left[\begin{array}{ccc}3.1&3.0\\3.(-2)&3.3\\\end{array}\right]$

   $\left[\begin{array}{ccc}5&3\\2&-4\\\end{array}\right]+\left[\begin{array}{ccc}3&0\\-6&9\\\end{array}\right]$

   $\left[\begin{array}{ccc}5+3&3+0\\2+(-6)&-4+9\\\end{array}\right]=\left[\begin{array}{ccc}8&3\\-4&5\\\end{array}\right]$