Question

Alguém me ajuda por favor preciso entregar esse trabalho urgente...​

Answer 1

Boa noite!!

Explicação passo-a-passo:

a)$1)\\\\log_ab=c\\1.1) log_264=c\\2^c = 64\\2 . 2 . 2 . 2.2.2 = 64 = 2^6\\log_264=6\\\\1.2)log_381=c\\\\3^c=81\\3^c=3^4\\log_381=4\\\\1.3)log(\sqrt{3} ) 81 = c\\\\\sqrt{3} = 3^{1/2} \\3^{c/2} =81 \\Analogamente, 3^x=81, x=4\\3^{x/2}=81, x=4\\Portanto,log(\sqrt{3})81 = 8\\\\1.4) log_{25}625=c\\\\25^c=625\\25^c=25^2\\c=2\\\\\d)6,4,8,2\\\\2)\\\\a)A=log{0,001}+log100\\log_{10}100=c\\10^c=100\\c=2\\\\0,001=1.10^{-3}\\A=log_{10}10^{-3} + 2\\A=-3.log_{10}10+2\\A=-3.1+2\\A=-1$$2)\\\\b)B=log_3(log_327)\\B=log_3(3)\\(log_aa=1)\\B=1$