Question

alguém me ajuda por favor eu preciso pra amanhã ​

Answer 1

Resposta:

=

2^(7/5) * (1/4)^(-7/21)

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(1/8)^(3/5) * (1/16)^(3/2)

=

2^(7/5) * (2^(-2))^(-7/21)

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(2^(-3))^(3/5) * (2^(-4))^(3/2)

=

2^(7/5) * (2)^(14/21)

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(2)^(-9/5) * (2)^(-12/2)

=  

2^(7/5 +14/21+9/5+12/2)

2^(7/5+2/3+9/5+6)

2^(16/5 +2/3+6)

2^(16/5 +2/3 +18/3)

2^(16/5 +20/3)

2^(48/15+100/15)

=2^(148/15)