Question

ALGUÉM ME AJUDA POR FAVOR!!!!

Answer 1

Resposta:

$b) \sqrt{ {5}^{3} } = \sqrt{ {5}^{2} } \times \sqrt{5} = 5 \sqrt{5}$

$c) \sqrt[3]{ {10}^{4} } = \sqrt[3]{ {10}^{3} } \times \sqrt[3]{10} = 10 \sqrt[3]{10}$

$d) \sqrt[4]{ {7}^{5} } = \sqrt[4]{ {7}^{4} } \times \sqrt[4]{7} = 7 \sqrt[4]{7}$

$f) \sqrt{ {a}^{5} } = \sqrt{ {a}^{2} } \times \sqrt{ {a}^{2} } \times \sqrt{a} = {a}^{2}\sqrt{a}$

$g) \sqrt[3]{ {x}^{7} } = \sqrt[3]{ {x}^{3} } \times \sqrt[3]{ {x}^{3} } \times \sqrt[3]{x} = {x}^{2} \sqrt[3]{x}$

$h) \sqrt[3]{ {m}^{8} } = \sqrt[3]{ {m}^{3} } \times \sqrt[3]{ {m}^{3} } \times \sqrt[3]{ {m}^{2} } = {m}^{2} \sqrt[3]{ {m}^{2 } }$

$i) \sqrt[5]{ {a}^{6}x } = \sqrt[5]{ {a}^{5} } \times \sqrt[5]{a} \times \sqrt[5]{x} = a \sqrt[5]{ax}$

$j) \sqrt{ {a}^{4} {y}^{3} } = \sqrt{ {a}^{2} } \times \sqrt{ {a}^{2} } \times \sqrt{ {y}^{2} } \times \sqrt{y} = {a}^{2} \times {y}^{2} \times \sqrt{y} = {a}^{2} {y}^{2} \sqrt{y}$