Question

alguém me Ajuda por favor ​

Answer 1

13)

A)

${x}^{2} - 5x + 6 = 0 \\ (x - 3)(x - 2) = 0 \\ \boxed{\boxed{ \green{x = 3 }}}\\\boxed{\boxed{\blue{ x = 2}}}$

B)

${x}^{2} - 10x + 24 \\ (x - 6)(x - 4) = 0 \\ \boxed{\boxed{\blue{x = 6}}} \\\boxed{\boxed{\green{ x = 4}}}$

c)

x²-4x-12=0

(x-6)(x+2)=0

x=6 ou x=-2

3)

3x²-15x+12=0

Δ=(-15)²-4×3×12

Δ=225-144

Δ=81

X=-(-15)±√81/6

x'=15+9/6

x'=24/6 ==>4

x''=15-9/6

x"=6/6=1

As medidas são: 4 e 1

p=4+4+1+1

p=10

A=b×h

A=4×1

A=4