Question

Alguém me ajuda pfv???
efetue:
a)√12-√75+√3=
b) 3√8-2√18+4√50=
c) 3√8+4√18=
d) √12-√8=

Answer 1

Resposta:

a)√12-√75+√3=√(4×3)-√(25×3)+√3=√4×√3-√25×√3+√3=

2×√3-5×√3+√3=√3×(2-5+1)= -2√3

b) 3√8-2√18+4√50=3×√(4×2)-2√(9×2)+4√(25×2)=

3×2√2-2×3√2+4×5√2= 20√2

c) 3√8+4√18= 3×√(4×2)-4√(9×2)=3×2√2-4×3√2= -6√2

d) √12-√8=√(4×3)-√(4×2)=2√3-2√2

Answer 2

Resposta:

$a) \red{ - 2 \sqrt{3} } \: \: \: \: \: b) \red{20 \sqrt{2} } \\ \\ \: \: \: \: \: c) \red{18 \sqrt{2} } \: \: \: \: \: d) \red{2 \sqrt{3} - 2 \sqrt{2} }$

Explicação passo-a-passo:

$a) \sqrt{12} - \sqrt{75} + \sqrt{3} \\ \sqrt{12} - \sqrt{75} + \sqrt{3} \\ \sqrt{12} \\ \sqrt{4 \times 3} \\ \sqrt{2 {}^{2} \times 3 } \\ \sqrt{2 {}^{2} } \sqrt{3} \\ 2 \sqrt{3} \\ \sqrt{12} - \sqrt{75} + \sqrt{3} \\ 2 \sqrt{3} - \sqrt{75} + \sqrt{3} \\ \sqrt{12} - \sqrt{75} + \sqrt{3} \\ \sqrt{75} \\ \sqrt{25 \times 3} \\ \sqrt{5 {}^{2} \times 3} \\ \sqrt{5 {}^{2} } \sqrt{3} \\ 5 \sqrt{3} \\ \sqrt{12} - \sqrt{75} + \sqrt{3} \\ 2 \sqrt{3} - 5 \sqrt{3} + \sqrt{3} \\ 2 \sqrt{3} - 5 \sqrt{3} + 1 \sqrt{3} \\ (2 - 5 + 1) \sqrt{3} \\ - 2 \sqrt{3} \\ 2 \sqrt{3} - 5 \sqrt{3} + \sqrt{3} \\ - 2 \sqrt{3} \\ resposta \\ - 2 \sqrt{3} \\ \\ b) 3\sqrt{8} - 2 \sqrt{18} + 4 \sqrt{50} \\ 3 \sqrt{8} - 2\sqrt{18} + 4 \sqrt{50} \\ 3 \sqrt{8} \\ 3 \sqrt{2 {}^{3} } \\ 3 \sqrt{2 {}^{2 + 1} } \\ 3 \sqrt{2 {}^{2} \times 2 {}^{1} } \\ 3 \sqrt{2 {}^{2} \times 2} \\ 3 \sqrt{2 {}^{2} } \sqrt{2} \\ 3 \times 2 \sqrt{2} \\ 6 \sqrt{2} \\ 3 \sqrt{8} - 2 \sqrt{18} + 4 \sqrt{50} \\ 6 \sqrt{2} - 2 \sqrt{18} + 4 \sqrt{50} \\ 3 \sqrt{8} - 2 \sqrt{18} + 4 \sqrt{50} \\ - 2 \sqrt{18} \\ - 2 \sqrt{9 \times 2} \\ - 2 \sqrt{3 {}^{2} \times 2 } \\ - 2 \sqrt{3 {}^{2} } \sqrt{2} \\ - 2 \times 3 \sqrt{2} \\ - 6 \sqrt{2} \\ 3 \sqrt{8} - 2 \sqrt{18} + 4 \sqrt{50} \\ 6 \sqrt{2} - 6 \sqrt{2} + 4 \sqrt{50} \\ 3 \sqrt{8} - 2 \sqrt{18} + 4 \sqrt{50} \\ 4 \sqrt{50} \\ 4 \sqrt{25 \times 2} \\ 4 \sqrt{5 {}^{2} \times 2 } \\ 4 \sqrt{5 {}^{2} } \sqrt{2} \\ 4 \times 5 \sqrt{2} \\ 20 \sqrt{2} \\ 3 \sqrt{8} - 2 \sqrt{18} + 4 \sqrt{50} \\ 6 \sqrt{2} - 6 \sqrt{2} + 20 \sqrt{2} \\ 20 \sqrt{2} \\ resposta \\ 20 \sqrt{2}$

$c)3 \sqrt{8} + 4 \sqrt{18} \\ 3 \sqrt{8} + 4 \sqrt{18} \\ 3 \sqrt{8} \\ 3 \sqrt{2 {}^{3} } \\ 3 \sqrt{2 {}^{2 + 1} } \\ 3 \sqrt{2 {}^{2} \times 2 {}^{1} } \\ 3 \sqrt{2 {}^{2} \times 2} \\ 3 \sqrt{2 {}^{2} } \sqrt{2} \\ 3 \times 2 \sqrt{2} \\ 6 \sqrt{2} \\ 3 \sqrt{8} + 4 \sqrt{18} \\ 6 \sqrt{2} + 4 \sqrt{18} \\ 3 \sqrt{8} + 4 \sqrt{18} \\ 4 \sqrt{18} \\ 4 \sqrt{9 \times 2} \\ 4 \sqrt{3 {}^{2} \times 2 } \\ 4 \sqrt{3 {}^{2} } \sqrt{2} \\ 4 \times 3 \sqrt{2} \\ 12 \sqrt{2} \\ 3 \sqrt{8} + 4 \sqrt{18} \\ 6 \sqrt{2} + 12 \sqrt{2} \\(6 + 2) \sqrt{2} \\ 18 \sqrt{2} \\ 6 \sqrt{2} + 12 \sqrt{2} \\ 18 \sqrt{2} \\ resposta \\ 18 \sqrt{2} \\ \\ d) \sqrt{12} - \sqrt{8} \\ \sqrt{12} - \sqrt{8} \\ \sqrt{12} \\ \sqrt{4 \times 3} \\ \sqrt{2 {}^{2} } \sqrt{3} \\ \sqrt{2 {}^{2} } \sqrt{3} \\ 2 \sqrt{3} \\ \sqrt{12} - \sqrt{8} \\2 \sqrt{3} - \sqrt{8} \\ \sqrt{12} - \sqrt{8} \\ \sqrt{8} \\ \sqrt{2 {}^{3} } \\ \sqrt{2 {}^{2 + 1} } \\ \sqrt{2 {}^{2} \times 2 {}^{1} } \\ \sqrt{2 {}^{2} \times 2} \\ \sqrt{2 {}^{2} } \sqrt{12} \\ 2 \sqrt{2} \\ \sqrt{12} - \sqrt{8} \\ 2 \sqrt{3} - 2 \sqrt{2} \\ resposta \\ 2 \sqrt{3} - 2 \sqrt{2}$