Question

ALGUEM ME AJUDA PFV!!!!

Answer 1

$\frac{38}{3\sqrt{3}-2\sqrt{2} }=$

$\frac{38}{3\sqrt{3}-2\sqrt{2} }\cdot \frac{3\sqrt{3}+2\sqrt{2}}{3\sqrt{3}+2\sqrt{2}} =$

$\frac{38(3\sqrt{3}+2\sqrt{2})}{9\cdot 3 +6\sqrt{6}-6\sqrt{6}-4\cdot 2 }=$

$\frac{38(3\sqrt{3}+2\sqrt{2})}{27-8}=$

$\frac{38(3\sqrt{3}+2\sqrt{2})}{19}=$

$2(3\sqrt{3}+2\sqrt{2})$

Gabarito: D) $2(3\sqrt{3}+2\sqrt{2})$