Question

alguém fazendo favor​

Answer 1

¡Hey!!

Resposta:

$a) \: ( { - 3x + 4b})^{2} \\ = ( - 3x + 4b).( - 3x + 4b) \\ = {9x}^{2} - 12xb - 12xb + {16b}^{2} \\ = {9x}^{2} - 24xb + {16x}^{2}$

$b) \: (5a + {2y})^{2} \\ = (5a + 2 {y}).(5a + 2y) \\ = {25a}^{2} + 10ay + 10ay + {4y}^{2} \\ = {25a}^{2} + 20ay + {4y}^{2}$

$c) \: ( {2x}^{2} + 3 {y}^{3} ) ^{2} \\ = ( {2x}^{2} + {3y}^{3} ).( {2x}^{2} + {3y}^{3} ) \\ = {4x}^{4} + 6 {x}^{2} {y}^{3} + {6 {x}^{2} y}^{3} + {9y}^{6} \\ = {4x}^{4} + {12 {x}^{2} {y}^{3} } + {9y}^{6}$

$d) \: (5z + 8).(5z - 8) \\ = {25z}^{2} - 45z + 45z - 64 \\ = {25z}^{2} -64$

$e) \: ( \frac{3}{2} + {2b})^{2} \\ = ( \frac{3}{2} + 2b).( \frac{3}{2} + 2 b) \\ = \frac{9}{4} + \frac{6b}{2} + \frac{6b}{2} + {2b}^{2} \\ = \frac{9}{4} + \frac{12b}{2} + {2b}^{2} \: \: \: \: \: \: \: \: \: \: \: \: \: = > mmc \\ = \frac{9}{4} + \frac{24b}{4} + \frac{ {8b}^{2} }{4} \\ = \frac{9 + 24b + {8b}^{2} }{4}$

¡Espero ter ajudado

- Bons estudos & Feliz Natal..