Question

alguem consegue resolver?

Answer 1

$Temos:\\\\ x=-0,1\ \ \ \ e\ \ \ \ \ y=0,001\\\\ F\'ormula:\\\\ \dfrac{-x^2+xy}{y}\\\\ Resolvendo:\\\\ \dfrac{-(-0,1)^2+(-0,1)(0,001)}{0,001}\\\\ =\dfrac{-0,01-0,0001}{0,001}\ \ (\times 10)\\\\ =\dfrac{-0,1-0,001}{0,01}\ \ (\times 10)\\\\ =\dfrac{-1-0,01}{0,1}\ \ (\times 10)\\\\ =\dfrac{-10-0,1}{1}\\\\ \boxed{=-10,1}$

Bons estudos!