Question

Alguém consegue me ajudar a resolver o x=((0,001)x(0.16)/1000)^1/4 e o y=(3^n+2/3^n-2)^1/4? Preciso do valor dos dois.

Answer 1

$x =[ \frac{(0,001)\cdot (0,16)}{1000}]^{\frac{1}{4}}\\ \\ x=[ \frac{16\cdot10^{-5}}{1000}]^{\frac{1}{4}}\\ \\ x=(16\cdot10^{-8})^\frac{1}{4}\\ \\ x=2\cdot10^{-2}\\ \\ \boxed{x=0,02}$

Agora Y:

$y=(\frac{3^{n+2}}{3^{n-2}})^\frac{1}{4}\\ \\ y=3^{(n+2-n+2)}^{\frac{1}{4}}\\ \\ y=3^{4\cdot\frac{1}{4}}\\ \\ y=3^{\frac{4}{4}}\\ \\ y=3^1\\ \\ \boxed{y=3}$

Agora, a soma:

$x+y = 0,02+3\\ \\ \boxed{x+y=3,02}$