Question

ALGUEM AJUDA QUESTÃO 9

Answer 1

$\sqrt[5]{\sqrt{243}}+\sqrt{\frac{3}{4}} +\sqrt{\frac{1}{3}}-\frac{5}{6}.\sqrt{3}$

$\sqrt[10]{243}+\frac{\sqrt{3}}{2}+\frac{1}{\sqrt{3}}-\frac{5\sqrt{3}}{6}$

$\sqrt[10]{3^5}+\frac{\sqrt{3}}{2}+\frac{\sqrt{3}}{3}-\frac{5\sqrt{3}}{6}$

$\sqrt{3}+ \frac{\sqrt{3}}{2}+\frac{\sqrt{3}}{3}-\frac{5\sqrt{3}}{6}$

$\frac{\sqrt{3}}{1}+\frac{3\sqrt{3}}{3.2}+\frac{2\sqrt{3}}{2.3}-\frac{5\sqrt{3}}{6}$

$\frac{6\sqrt{3}}{6.1}+\frac{3\sqrt{3}}{6}+\frac{2\sqrt{3}}{6}-\frac{5\sqrt{3}}{6}$

$\frac{6\sqrt{3}}{6}+\frac{3\sqrt{3}}{6}+\frac{2\sqrt{3}}{6}-\frac{5\sqrt{3}}{6}$

$\frac{6\sqrt{3}+3\sqrt{3}+2\sqrt{3}-5\sqrt{3}}{6}$

$\frac{6\sqrt{3}}{6}$

$\sqrt{3}$