Question

Alguem ajuda por favooor!!!!
Determine a distância d e o ponto médio M entre as coordenadas A(3,-2) e B(3,2). *
a) d = 4 e M (3, 0)
b) d = 16 e M (-3,2)
c) d = 8 e M ( 0, 4)
d) d = 4 e M (-3, 0)
e) d = 4 e M (3, 2)

Answer 1

$\mathsf{{(x_{B}-x_{A}) }^{2}={(3-3)}^{2}={0}^{2}=0}$

$\mathsf{{(y_{B}-y_{A}) }^{2}={(2-[-2]) }^{2}={(2+2)}^{2}=16}$

$\mathtt{d_{A, B}=\sqrt{{(x_{B}-x_{A})}^{2}+{(y_{B}-y_{A})}^{2}}}$

$\mathtt{d_{A, B}=\sqrt{0+16}=\sqrt{16}=4}$

$\mathsf{x_{M}=\dfrac{x_{A}+x_{B}}{2}=\dfrac{3+3}{2}=3}$

$\mathsf{y_{M}=\dfrac{y_{A}+y_{B}}{2}=\dfrac{-2+2}{2}=0}$

M(3,0)

$\boxed{\boxed{\mathsf{\maltese~~Alternativa~A}}}$