Question

alguém ajuda nessa função? -x²+3/2x+1=0

Answer 1

Oii,
Vamos resolver utilizando Bhaskara:

$-x^2 + \frac{3}{2} x + 1 = 0$
Δ = $( \frac{3}{2} )^2 - 4*(-1)*1$
Δ = $\frac{9}{4} + 4$
Δ = $\frac{9+16}{4} = \frac{25}{4}$

$x = \frac{- \frac{3}{2}(+-) \sqrt{\frac{25}{4} }}{2*(-1)}$
$x = \frac{- \frac{3}{2}(+-) \frac{5}{2} }{-2}$
$x' = \frac{- \frac{3}{2}+ \frac{5}{2} }{-2} = \frac{ \frac{2}{2}}{-2} = \frac{1}{-2} = -0,5$
$x'' = \frac{- \frac{3}{2}- \frac{5}{2} }{-2} = \frac{ \frac{-8}{2}}{-2} = \frac{-4}{-2} = 2$

$\boxed{Raizes = (-0,5 ; 2)}$