Question

algm me ajuda plmds aaaaaaaa

Answer 1

Resposta:

$27^x=9^y\\ \\ 3^{3x}=3^{2y}\\ \\ \boxed{3x=2y}$

$\log_yx=2\\ \\\boxed{ y^2=x}$

Substituir x em:

$3x=2y\\ \\ 3y^2=2y\\ \\ 3y^2-2y=0\\ \\ y(3y-2)=0\\ \\ 3y-2=0\\ \\ 3y=2\\ \\\boxed{ y=\dfrac{2}{3}}$

$Sendo~~~3x=2y\\ \\ 3x=2.(\dfrac{2}{3})\\ \\ \\ 3x=\dfrac{4}{3}\\ \\ 9x=4\\ \\\boxed{ x=\dfrac{4}{9}}$

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Soma de x + y

$\dfrac{4}{9}+\dfrac{2}{3}=\\ \\ mmv(3,9)=9\\ \\ \\ \dfrac{4+6}{9}=\boxed{\dfrac{10}{9}}$