Ajudeem!!
Logarítimos
(A) log5 (5a/bc)
(B) log3 (a* b^3/c * raiz cubica de a²)
korvo:
entendeu Carol???
Soluções para a tarefa
Respondido por
24
Propriedades:
![log _{n}(xy)\to~log _{n}x*log _{n}y~\to~log _{n}x+log _{n}y~~(LOG~DO~PRODUTO)\\\\
log _{n}( \frac{x}{y})\to~log _{n}x/log _{n}y~\to~log _{n}x-log _{n}y~(LOG~DO~QUOCIENTE)\\\\
logx ^{n}~\to~n*log~~(LOG~DA~POTENCIA)\\\\
log _{x}y=n~\to~x ^{n}=y
log _{n}(xy)\to~log _{n}x*log _{n}y~\to~log _{n}x+log _{n}y~~(LOG~DO~PRODUTO)\\\\
log _{n}( \frac{x}{y})\to~log _{n}x/log _{n}y~\to~log _{n}x-log _{n}y~(LOG~DO~QUOCIENTE)\\\\
logx ^{n}~\to~n*log~~(LOG~DA~POTENCIA)\\\\
log _{x}y=n~\to~x ^{n}=y](https://tex.z-dn.net/?f=log+_%7Bn%7D%28xy%29%5Cto%7Elog+_%7Bn%7Dx%2Alog+_%7Bn%7Dy%7E%5Cto%7Elog+_%7Bn%7Dx%2Blog+_%7Bn%7Dy%7E%7E%28LOG%7EDO%7EPRODUTO%29%5C%5C%5C%5C%0Alog+_%7Bn%7D%28+%5Cfrac%7Bx%7D%7By%7D%29%5Cto%7Elog+_%7Bn%7Dx%2Flog+_%7Bn%7Dy%7E%5Cto%7Elog+_%7Bn%7Dx-log+_%7Bn%7Dy%7E%28LOG%7EDO%7EQUOCIENTE%29%5C%5C%5C%5C%0Alogx+%5E%7Bn%7D%7E%5Cto%7En%2Alog%7E%7E%28LOG%7EDA%7EPOTENCIA%29%5C%5C%5C%5C%0Alog+_%7Bx%7Dy%3Dn%7E%5Cto%7Ex+%5E%7Bn%7D%3Dy+++%0A+++++)
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![log _{5}( \frac{5a}{bc})=log _{5} 5a-log _{5}bc\\\\
log _{5}( \frac{5a}{bc})=(log _{5}5*log _{5}a)-log _{5}b*log _{5}c\\\\
log _{5}( \frac{5a}{bc})=(log _{5}5+log _{5}a)-log _{5}b+log _{5}c\\\\
\boxed{log _{5}( \frac{5a}{b})=(1+log _{5}a)-log _{5}b+log _{5}c} log _{5}( \frac{5a}{bc})=log _{5} 5a-log _{5}bc\\\\
log _{5}( \frac{5a}{bc})=(log _{5}5*log _{5}a)-log _{5}b*log _{5}c\\\\
log _{5}( \frac{5a}{bc})=(log _{5}5+log _{5}a)-log _{5}b+log _{5}c\\\\
\boxed{log _{5}( \frac{5a}{b})=(1+log _{5}a)-log _{5}b+log _{5}c}](https://tex.z-dn.net/?f=log+_%7B5%7D%28+%5Cfrac%7B5a%7D%7Bbc%7D%29%3Dlog+_%7B5%7D+5a-log+_%7B5%7Dbc%5C%5C%5C%5C%0Alog+_%7B5%7D%28+%5Cfrac%7B5a%7D%7Bbc%7D%29%3D%28log+_%7B5%7D5%2Alog+_%7B5%7Da%29-log+_%7B5%7Db%2Alog+_%7B5%7Dc%5C%5C%5C%5C%0Alog+_%7B5%7D%28+%5Cfrac%7B5a%7D%7Bbc%7D%29%3D%28log+_%7B5%7D5%2Blog+_%7B5%7Da%29-log+_%7B5%7Db%2Blog+_%7B5%7Dc%5C%5C%5C%5C%0A%5Cboxed%7Blog+_%7B5%7D%28+%5Cfrac%7B5a%7D%7Bb%7D%29%3D%281%2Blog+_%7B5%7Da%29-log+_%7B5%7Db%2Blog+_%7B5%7Dc%7D++++++++++++++++++)
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![log _{3}( \frac{ab ^{3} }{c \sqrt[3]{a ^{2} } })=log _{3}(ab ^{3})-log _{3}c \sqrt[3]{a ^{2} }\\\\
log _{3}( \frac{ab ^{3} }{ c\sqrt[3]{a ^{2} } })=(log _{3}a*log _{3}b ^{3})-log _{3}(c*a ^{ \frac{2}{3} })\\\\
log _{3}( \frac{ab ^{3} }{c \sqrt[3]{a ^{2} } })=(log _{3}a+3*log_{3}b)-log _{3}c*log_{3}a ^{ \frac{2}{3} }\\\\
log _{3}( \frac{ab ^{3} }{c \sqrt[3]{a ^{2} } })=(log _{3}a+3log _{3}b)-log _{3}c+ \frac{2}{3}*log _{3}a log _{3}( \frac{ab ^{3} }{c \sqrt[3]{a ^{2} } })=log _{3}(ab ^{3})-log _{3}c \sqrt[3]{a ^{2} }\\\\
log _{3}( \frac{ab ^{3} }{ c\sqrt[3]{a ^{2} } })=(log _{3}a*log _{3}b ^{3})-log _{3}(c*a ^{ \frac{2}{3} })\\\\
log _{3}( \frac{ab ^{3} }{c \sqrt[3]{a ^{2} } })=(log _{3}a+3*log_{3}b)-log _{3}c*log_{3}a ^{ \frac{2}{3} }\\\\
log _{3}( \frac{ab ^{3} }{c \sqrt[3]{a ^{2} } })=(log _{3}a+3log _{3}b)-log _{3}c+ \frac{2}{3}*log _{3}a](https://tex.z-dn.net/?f=log+_%7B3%7D%28+%5Cfrac%7Bab+%5E%7B3%7D+%7D%7Bc+%5Csqrt%5B3%5D%7Ba+%5E%7B2%7D+%7D+%7D%29%3Dlog+_%7B3%7D%28ab+%5E%7B3%7D%29-log+_%7B3%7Dc+%5Csqrt%5B3%5D%7Ba+%5E%7B2%7D+%7D%5C%5C%5C%5C%0Alog+_%7B3%7D%28+%5Cfrac%7Bab+%5E%7B3%7D+%7D%7B+c%5Csqrt%5B3%5D%7Ba+%5E%7B2%7D+%7D+%7D%29%3D%28log+_%7B3%7Da%2Alog+_%7B3%7Db+%5E%7B3%7D%29-log+_%7B3%7D%28c%2Aa+%5E%7B+%5Cfrac%7B2%7D%7B3%7D+%7D%29%5C%5C%5C%5C%0Alog+_%7B3%7D%28+%5Cfrac%7Bab+%5E%7B3%7D+%7D%7Bc+%5Csqrt%5B3%5D%7Ba+%5E%7B2%7D+%7D+%7D%29%3D%28log+_%7B3%7Da%2B3%2Alog_%7B3%7Db%29-log+_%7B3%7Dc%2Alog_%7B3%7Da+%5E%7B+%5Cfrac%7B2%7D%7B3%7D+%7D%5C%5C%5C%5C%0Alog+_%7B3%7D%28+%5Cfrac%7Bab+%5E%7B3%7D+%7D%7Bc+%5Csqrt%5B3%5D%7Ba+%5E%7B2%7D+%7D+%7D%29%3D%28log+_%7B3%7Da%2B3log+_%7B3%7Db%29-log+_%7B3%7Dc%2B+%5Cfrac%7B2%7D%7B3%7D%2Alog+_%7B3%7Da++++++++++++++++++++++++++++)
![log _{3}( \frac{ab ^{3} }{c \sqrt[3]{a ^{2} } })=(log _{3}a+3log _{3}b)-log _{3}c+ \frac{2}{3}log _{3}a\\\\
log _{3}( \frac{ab ^{3} }{c \sqrt[3]{a ^{2} } })= (\frac{2}{3}log _{3}a+log _{3}a+3log _{3}b)-log _{3}c\\\\
\boxed{log _{3}( \frac{ab ^{3} }{c \sqrt[3]{a ^{2} } })=\frac{5}{3}log _{3}a+3log _{3}b-log _{3}c} log _{3}( \frac{ab ^{3} }{c \sqrt[3]{a ^{2} } })=(log _{3}a+3log _{3}b)-log _{3}c+ \frac{2}{3}log _{3}a\\\\
log _{3}( \frac{ab ^{3} }{c \sqrt[3]{a ^{2} } })= (\frac{2}{3}log _{3}a+log _{3}a+3log _{3}b)-log _{3}c\\\\
\boxed{log _{3}( \frac{ab ^{3} }{c \sqrt[3]{a ^{2} } })=\frac{5}{3}log _{3}a+3log _{3}b-log _{3}c}](https://tex.z-dn.net/?f=log+_%7B3%7D%28+%5Cfrac%7Bab+%5E%7B3%7D+%7D%7Bc+%5Csqrt%5B3%5D%7Ba+%5E%7B2%7D+%7D+%7D%29%3D%28log+_%7B3%7Da%2B3log+_%7B3%7Db%29-log+_%7B3%7Dc%2B+%5Cfrac%7B2%7D%7B3%7Dlog+_%7B3%7Da%5C%5C%5C%5C%0Alog+_%7B3%7D%28+%5Cfrac%7Bab+%5E%7B3%7D+%7D%7Bc+%5Csqrt%5B3%5D%7Ba+%5E%7B2%7D+%7D+%7D%29%3D+%28%5Cfrac%7B2%7D%7B3%7Dlog+_%7B3%7Da%2Blog+_%7B3%7Da%2B3log+_%7B3%7Db%29-log+_%7B3%7Dc%5C%5C%5C%5C%0A%5Cboxed%7Blog+_%7B3%7D%28+%5Cfrac%7Bab+%5E%7B3%7D+%7D%7Bc+%5Csqrt%5B3%5D%7Ba+%5E%7B2%7D+%7D+%7D%29%3D%5Cfrac%7B5%7D%7B3%7Dlog+_%7B3%7Da%2B3log+_%7B3%7Db-log+_%7B3%7Dc%7D++++++++++++++++++++)
Espero ter ajudado e tenha ótimos estudos xD
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Espero ter ajudado e tenha ótimos estudos xD
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