Question

Ajudeeeeeeem pf pessoal

Answer 1

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ABD
$\tan(30) = \frac{ \sqrt{3} }{3}$

tan30°=x/600
√3/3=x/600
3x=600√3
x=600√3/3
x=200√3
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x=BD
$\sin(45) = \frac{ \sqrt{2} }{2}$

sin45°=h/200√3
√2/2=h/200√3
2h=200√3.√2
2h=200√6
h=200√6/2
h=100√6