Question

AJUDEEEEEEEEEEEEEMM
Dada as funçoes f(x)=x^2+1 e g(x)=3x-4, determine:

a) f(g(x))
b) f(g(0))
c) g(f(x))]
d) g(f(1))

Answer 1

$a) \ f(g(x))=(3x-4)^2+1=9x^2-24x+16+1=9x^2-8x+1\\ \\ f(g(0))=9.0^2-8.0+1=1\\ \\ g(f(x))=3(x^2+1)-4=3x^2+3-4=3x^2-1\\ \\ g(f(1))=3.1^2-1=3-1=2$