Question

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$(9a^ 2 +6ab+4b^ 2 ).(3a-2b)$
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Answer 1

Resposta:

(9a²+6ab+4b²) *(3a-2b)

= 9a²*(3a-2b) +6ab*(3a-2b) +4b²*(3a-2b)

=27a³ -18a²b+18a²b -12ab²+12b²a-8b³

=27a³ -8b³

=(3a)³-(2b)³

Answer 2

$=9a^2\cdot \:3a+9a^2\left(-2b\right)+6ab\cdot \:3a+6ab\left(-2b\right)+4b^2\cdot \:3a+4b^2\left(-2b\right)\\=27a^3-18a^2b+18a^2b-12ab^2+12ab^2-8b^3\\=27a^3-12ab^2+12ab^2-8b^3\\=27a^3-8b^3$