Question

ajudaaaa
1 - Simplifique as expressões aplicando as propriedades de potenciação
estudadas:
a) 23.25 =
b) 3-4. 36 =
c) (-9).(-9). (-9)5 =
d) 75: 73 =
e) 103: 105 =
f) 512 : 55 =
g) (73)4 =
h) (205)-2 =
i) (-43)3 =
1) (23)2 =​

Answer 1

Explicação passo-a-passo:

a) $\sf 2^3\cdot2^5=2^{3+5}=2^8$

b) $\sf 3^{-4}\cdot3^6=3^{-4+6}=3^2$

c) $\sf (-9)\cdot(-9)\cdot(-9)^5=(-9)^{1+1+5}=(-9)^7$

d) $\sf 7^5\div7^3=7^{5-3}=7^2$

e) $\sf 10^3\div10^5=10^{3-5}=10^{-2}$

f) $\sf 5^{12}\div5^{5}=5^{12-5}=5^7$

g) $\sf (7^3)^4=7^{3\cdot4}=7^{12}$

h) $\sf (20^5)^{-2}=20^{5\cdot(-2)}=20^{-10}$

i) $\sf [(-4)^{3}]^3=(-4)^{3\cdot3}=(-4)^9$

j) $\sf (2^3)^2=2^{3\cdot2}=2^6$

Answer 2

Oie, Td Bom?!

a)

$2 {}^{3} \: . \: 2 {}^{5} = 2 {}^{3 + 5} = 2 {}^{8}$

b)

$3 {}^{ - 4} \: . \: 3 {}^{6} = 3 {}^{ - 4 + 6} = 3 {}^{2}$

c)

$( - 9) \: . \: ( - 9) \: . \: ( - 9) {}^{5} = ( - 9) {}^{1 + 1 + 5} = ( - 9) {}^{7}$

d)

$7 {}^{5} \div 7 {}^{3} = 7 {}^{5 - 3} = 7 {}^{2}$

e)

$10 {}^{3} \div 10 {}^{5} = 10 {}^{3 - 5} = 10 {}^{ - 2}$

f)

$5 {}^{12} \div 5 {}^{5} = 5 {}^{12 - 5} = 5 {}^{7}$

g)

$(7 {}^{3} ) {}^{4} = 7 {}^{3 \: . \: 4} = 7 {}^{12}$

h)

$(20 {}^{5} ) {}^{ - 2} = 20 {}^{5 \: . \: ( - 2)} = 20 {}^{ - 10}$

i)

$( - 4 {}^{3} ) {}^{3} = - (4 {}^{3} ) {}^{3} = - 4 {}^{3 \: . \: 3} = - 4 {}^{9}$

j)

$(2 {}^{3} ) {}^{2} = 2 {}^{3 \: . \: 2} = 2 {}^{6}$

Att. Makaveli1996