Question

ajudaaa pfvr
Dados log 2=0,3010,
log 3=0,4771,
log 10=1, calcule;

a) log 72
b) log 200
c) log 144
d) log 20​

Answer 1

Resposta:

Explicação passo-a-passo:

log72= log2^3.3^2= log2^3+log3^2= 3.log2+2.log3= 3.0,3+2.0,4=0,9+0,8=1,7

log200= log2.100=log2+log100= 0,3+2= 2,3

log 144= log2^4.3^2=log2^4+log3^2= 4.log2+2.log3= 4.0,3+ 2.0,4=2

log20= log2.10= log2+log10= 0,3+1= 1,3