Question

AJUDAA!

$A) \frac{ x^{2} }{3} (0,9x ^{2} +2,7x+ \frac{3}{2} )$

$B)(-3xy)(2xy ^{2} + \frac{ x^{2} y}{2} - x^{2} )$

Answer 1

Só aplicar a distributiva:

$x(a+b+c)=x.a+x.b+x.c$

Parte literal multiplica parte literal, coeficiente multiplica coeficiente

Lembrando:

$a^{x}*a^{y}=a^{x+y}$
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a)

$\frac{x^{2}}{3}(0,9x^{2}+2,7x+\frac{3}{2})=\frac{x^{2}}{3}.0,9x^{2}+\frac{x^{2}}{3}.2,7x+\frac{x^{2}}{3}.\frac{3}{2}\\\\\frac{x^{2}}{3}(0,9x^{2}+2,7x+\frac{3}{2})=0,3.x^{2}.x^{2}+x^{2}.0,9x+\frac{x^{2}}{2}\\\\\frac{x^{2}}{3}(0,9x^{2}+2,7x+\frac{3}{2})=0,3x^{4}+0,9x^{3}+\frac{x^{2}}{2}$

b)

$(-3xy)(2xy^{2}+\frac{x^{2}y}{2}-x^{2})=(-3xy).2xy^{2}+(-3xy).\frac{x^{2}y}{2}-(-3xy).x^{2}\\\\(-3xy)(2xy^{2}+\frac{x^{2}y}{2}-x^{2})=-6x^{2}y^{3}-\frac{3x^{3}y^{2}}{2}+3x^{3}y$