Question

Ajuda pfvr é urgente

Answer 1

Resposta:

Explicação passo a passo:

$1)$

$a)$

$\sqrt{8} .\sqrt{8} =\sqrt{64} =8$

$b)$

$\sqrt{2} .\sqrt{60,5} =\sqrt{121} =11$

$c)$

$\frac{\sqrt{4} }{\sqrt{144} } =\frac{2}{12} =\frac{1}{6}$

$2)$

$\sqrt[16]{2^{8} } =\sqrt[16:2]{2^{8:2} } =\sqrt[8]{2^{4} }$

$Portanto\:\:x=8$

$3)$

$\sqrt[2]{3}$

$\sqrt[3]{5}$

$\sqrt[4]{2}$

$mmc(2;3;4)=12$

$\sqrt[2]{3}=\sqrt[12]{3^{6} }$

$\sqrt[3]{5}=\sqrt[12]{5^{4} }$

$\sqrt[4]{2}=\sqrt[12]{2^{3} }$

$4)$

$\sqrt[3]{2.(\sqrt{9}+2.\sqrt{25})+1} =$

$\sqrt[3]{2.(3+2.5)+1} =$

$\sqrt[3]{2.(3+10)+1}=$

$\sqrt[3]{2.13+1}=$

$\sqrt[3]{26+1} =$

$\sqrt[3]{27} =$

$3$

$5)$

$a)$

$(\sqrt{5}) ^{3} =\sqrt{5^{3} } =\sqrt{5^{2}.5 } =5\sqrt{5}$

$b)$

$\sqrt{\frac{1}{16} } =\frac{\sqrt{1} }{\sqrt{16} } =\frac{1}{4}$

$c)$

$\frac{\sqrt[5]{13} }{\sqrt[5]{9} } =\sqrt[5]{\frac{13}{9} }$