Question

ajuda euuuuu

$log_{4}16$
$log_381$
$log_{5}125$
$log_{8}64$
$log_232$
​

Answer 1

$\mathtt{log_{4}16=log_{{2}^{2}}{2}^{4}=\dfrac{4}{2}=2}$

$\mathtt{log_{3}81=log_{{3}^{1}}{3}^{4}=\dfrac{4}{1}=4}$

$\mathtt{log_{5}125=log_{{5}^{1}}{5}^{3}=\dfrac{3}{1}=3}$

$\mathtt{log_{8}64=log_{{2}^{3}}{2}^{6}=\dfrac{6}{3}=2}$

$\mathtt{log_{2}32=log_{{2}^{1}}{2}^{5}=\dfrac{5}{1}=5}$

Answer 2

$a)log_{4}16 \\ {4}^{x} = 16 \\ {4}^{x} = {4}^{2} \\ x = 2$

$b) log_{3}(81) \\ {3}^{x} = 81 \\ {3}^{x} = {3}^{4} \\ x = 4$

$c) log_{5}(125) \\ {5}^{x} = 125 \\ {5}^{x} = {5}^{3} \\ x = 3$

$d)log_{8}(64) \\ {8}^{x} = 64 \\ {8}^{x} = {8}^{2} \\ x = 2$

$c) log_{2}(32) \\ {2}^{x} = 32 \\ {2}^{x} = {2}^{5} \\ x = 5$