Question

ajuda ai pff................................

Answer 1

$\left(-2\right)^3+\left(-2\right)^4+2021^0+11\cdot \:1^3\\\\=-8+\left(-2\right)^4+2021^0+11\cdot \:1^3\\\\=-8+16+2021^0+11\cdot \:1^3\\\\=-8+16+1+11\cdot \:1^3\\\\=-8+16+1+11\cdot \:1\\\\=-8+16+1+11\\\\=20$  $3^0\left(\sqrt{64}-\sqrt{9}-\sqrt{0}\right)\\\\=3^0\left(\sqrt{64}-0-\sqrt{9}\right)\\\\3^0=1\\=1\cdot \left(\sqrt{64}-0-\sqrt{9}\right)\\\\=1\cdot \left(8-3-0\right)\\\\8-3-0=5\\\\=1\cdot \:5\\\\=5$

E = 20

F = 5

E $\div$ F

20 $\div$ 5 = 4

Resultado Final > Letra A = 4