Question

Agora e a sua vez de resolver. Boa sorte
a) 2.(2x-1) = 28
b) 2.(3x-2) = 4
c)2.(4x-1)=14
d)3.(4x+4)=24
e) 5 (2x+30) = 160
f)4.(x+1)=44​

Answer 1

Explicação passo-a-passo:

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a)

$\sf{2.(2x-1) = 28} \\ \sf{4x - 2 = 28} \\ \sf{4x = 28 + 2} \\ \sf{4x = 30} \\ \boxed{\red{ \sf{ \frac{30}{4} }}}$

b)

$\sf{2.(3x-2) = 4} \\ \sf{6x - 4 = 4} \\ \sf{6x = 4 + 4} \\ \sf{6x = 8} \\ \boxed{\red{ \sf{x = \frac{8}{6} }}}$

c)

$\sf{2.(4x-1)=14 } \\ \sf{8x - 2 = 14} \\ \sf{8x = 14 + 2} \\ \sf{8x = 16} \\ \sf{x = \frac{16}{8} } \\ \boxed{\red{ \sf{x = 2}}}$

d)

$\sf{3.(4x+4)=24 } \\ \sf{12x + 12 = 24} \\ \sf{12x = 24 - 12} \\ \sf{12x = 12} \\ \sf{x = \frac{12}{12} } \\ \boxed{\red{ \sf{x = 1}}}$

e)

$\sf{5.(2x+30) = 160} \\ \sf{10x + 150 = 160} \\ \sf{10x = 160 - 150} \\ \sf{10x = 10} \\ \sf{x = \frac{10}{10} } \\ \boxed{\red{ \sf{x = 1}}}$

f)

$\sf{4.(x+1)=44} \\ \sf{4x + 4 = 44} \\ \sf{4x = 44 - 4} \\ \sf{4x = 40} \\ \sf{x = \frac{40}{4} } \\ \boxed{\red{ \sf{x = 4}}}$

$\mathcal{ATT : ARMANDO} \\ \mathfrak{\small04\diagup01\diagup2021} \\ \mathfrak{\small{10} :{18} \: \: pm}$