Question

admitindo que log2=0,301,entao calcule log5.

Answer 1

log5 = log(10/2) = log10 - log2 = 1 - 0,301= 0,699

log10 = 1 pois 10¹ = 10

Answer 2

Olá Jardenylson

log(2) = 0.301
log(10) = 1

log(5) = log(10/2) = log(10) - log(2) 

log(5) = 1 - log(2)

log(5) = 1 - 0.301 = 0.699 

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