Question

Achar o zero da funçao. X2+7×+10

Answer 1

vamos lá....

x² +7x +10=0

a=1
b=7
c=10

Δ=b²-4ac
Δ=7²-4(1)(10)
Δ=49-40
Δ=9

$x= \frac{-b\pm \sqrt{\triangle} }{2a} =~~ \frac{-7\pm \sqrt{9} }{2} =~~ \frac{-7\pm3}{2} \\ \\ x'= \frac{-7+3}{2} =- \frac{4}{2} =-2 \\ \\ x"= \frac{-7-3}{2} =- \frac{10}{2} =-5$

Answer 2

x ²+7x+10=O {a= 1 b= 7 c= 10}

Δ= b²-4.a.c
Δ= 7²-4.1.10
Δ= 49-40
Δ= 9

x = – b ± √∆
2∙a

x = – 7 ± √9
2∙1

x = – 7 ± 3
2

X1 = – 7 + 3
2
X1= -4/2= -2

X2= -7 -3
2
X2= -10/2= -5