Question

achar a raiz da equacao x²-7x+10=0

Answer 1

$x^{2} -7x+10=0\ Delta= b^{2} -4.a.c \Delta= -7^{2} -4.1.10\ Delta=49-40=9$
$x1=-+(-7) \sqrt{9} /2=7-9/2=3/2 x2=-+(-7) \sqrt{9} /2=7+9/2=16/2=8$