Question

a. y=(∜5x 2)/√(-2x 4)

b. y=(3x+1)/(√x-3)

Answer 1

$Ola' \\ \\ Sendo~a~express\~ao: \\ \\ y= \frac{ \sqrt[4]{5 x^{2} } }{ \sqrt{-2 x^{4} } } \\ \\ \underline{resoluc\~ao~ } \\ \\ y= \frac{ \sqrt{5x} }{ -2 x^{2} } } \\ \\ y= - \frac{ \sqrt{5} }{2}. \sqrt{ \frac{1}{ x^{3} } } \\ \\ y=- \frac{ \sqrt{5} }{2}. \sqrt{ x^{-3} }$

$\boxed{y=- \frac{ \sqrt{5 x^{-3} } }{2} }~-----\ \textgreater \ [A] \\ \\ =============================== \\ y= \frac{3x+1}{ \sqrt{x} -3} \\ \\ \underline{resoluc\~ao} \\ \\ y= \frac{(3x+1).( \sqrt{x} +3)}{( \sqrt{x} -3).( \sqrt{x} +3)} \\ \\ y= \frac{3x \sqrt{x} +9x+ \sqrt{x} +3}{x-9} \\ \\ \boxed{y= \frac{( \sqrt{x} +3)(3x+1)}{x-9}}~~---\ \textgreater \ [B] \\ \\ =============================== \\~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~Espero~ter~ajudado!!$