Question

a) x²-7=x + 5x
b) x²+11x= 16x-6x

Answer 1

Explicação passo-a-passo:

x²-7=x + 5x

x²-x-5x-7=0

x²-6x-7=0

a=1

b=-6

c=-7

∆=b²-4ac

∆=(-6)²-4×1×-7

∆=36+28

∆=64

-b±√∆/2a

6±√64/2×1

6±8/2

x¹=6+8/2=14/2=7

x²=6-8/2=-2/2=-1

x²+11x= 16x-6x

x²+11x-16x+6x=0

x²-5x+6x=0

x²+x=0

x(x+1)=0

x+1=0

x=0-1

x=-1

s={0,-1}