Question

a) x² + 6x + 8 = 0
$x { }^ { 2 } + 6 \times + 8 = 0$
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Answer 1

x² + 6x + 8= 0

A= 1

B= 6

C= 8

∆= b² - 4ac

∆= 6² - 4 • 1 • 8

∆= 36 - 32

∆= 4

x= - b ± √∆/2a

x= - 6 ± √4/2 • 1

x= - 6 ± 2/2

x'= - 6 + 2/2 = - 4/2 = - 2

x''= - 6 - 2/2 = - 8/2 = - 4

S= (- 4 , - 2)