Question

a ) x² - 2x + 1 = 0
b ) x² - 6x - 16 = 0
C ) x² - 2x + 1 = 0

Por Favor, Min Ajudem Nessa Equação ​

Answer 1

Resposta:

a) e c) x = 1

b) x' = 8 e x'' = -2

Explicação passo a passo:

a) e c) Sejam a = 1, b = -2 e c = 1:

$delta = b^{2} - 4.a.c\\delta = (-2)^{2} - 4.(1).(1) \\delta = 4 - 4 \\delta = 0$

Logo:

$x = \frac{-b +/- \sqrt{delta}}{2.a} \\x = \frac{-(-2) +/- \sqrt{0}}{2.(1)}\\x = \frac{2 +/- 0}{2}\\\\x = 1$

b) Sejam a = 1, b = -6 e c = -16

$delta = b^{2} - 4.a.c\\delta = (-6)^{2} - 4.(1).(-16) \\delta = 36 + 64 \\delta = 100$

Logo:

$x = \frac{-b +/- \sqrt{delta}}{2.a} \\x = \frac{-(-6) +/- \sqrt{100}}{2.(1)}\\x = \frac{6 +/- 10}{2}\\\\\x' = \frac{16}{2} = 8\\x'' = \frac{-4}{2} = -2$